Oops! I take that back. I just re-read the original post.
On Fri, Aug 21, 2009 at 7:55 AM, brian<bally.z...@gmail.com> wrote:
> I don't think albe is trying to update existing records, though. And,
> anyway, with your example, $value1 is never assigned.
>
> On Fri, Aug 21, 2009 at 7:17 AM, delocalizer<conrad.leon...@hotmail.com>
> wrote:
>>
>> updateAll is the way to go...
>> eg. $this->Post->updateAll(array('options'=>value2),array('id <>
>> '=>'$var));
>> reducing the number of transactions in this case from n(Posts) to just
>> 2 - one for the matching record and one for all the rest.
>>
>> On Aug 21, 8:45 pm, brian <bally.z...@gmail.com> wrote:
>>> Almost, but $value_2 will never be assigned. Perhaps the OP could shed
>>> some light on the bigger picture as there may be a better way to
>>> approach this.
>>>
>>> On Fri, Aug 21, 2009 at 5:07 AM, rich...@home<richardath...@gmail.com>
>>> wrote:
>>>
>>> > You don't need the else branch in the 2nd example, its taken care of
>>> > in the read:
>>>
>>> > // fetch back the record with an id of $var
>>> > $post = $this->Post->read(null, $var);
>>>
>>> > // update the record
>>> > $post['Post']['options'] = value1;
>>>
>>> > // save the record
>>> > $this->Post->save($post);
>>>
>>> > In the first example, you fetch back a number of records and loop
>>> > through them looking for one with an id of $var. It's quite likely
>>> > that id will be unique (its should be a primary key) so there's no
>>> > need for the loop.
>>>
>>> > On Aug 20, 5:21 pm, albe <radialremo...@gmail.com> wrote:
>>> >> foreach($posts as $p) {
>>>
>>> >> if ($p['Post']['id'] == $var) {
>>> >> $p['Post']['options'] = value1;
>>> >> } else {
>>> >> $p['Post']['options'] = value 2;
>>> >> }
>>> >> $this->Post->save($p);
>>>
>>> >> }
>>>
>>> >> This works! I just can't say how much I am grateful for your help!
>>> >> However I still don't understand why my code was wrong...
>>>
>>> >> About your second way:
>>>
>>> >> $post = $this->Post->read(null, $var);
>>> >> $post['Post']['options'] = value1;
>>> >> $this->Post->save($post);
>>>
>>> >> If I use this, where shall i put the ELSE branch?
>>>
>>> >> On 20 Ago, 18:00, "rich...@home" <richardath...@gmail.com> wrote:
>>>
>>> >> > Shouldn't that be:
>>>
>>> >> > foreach($posts as $p) {
>>>
>>> >> > if ($p['Post']['id'] == $var) {
>>> >> > $p['Post']['options'] = value1;
>>> >> > } else {
>>> >> > $p['Post']['options'] = value 2;
>>> >> > }
>>> >> > $this->Post->save($p);
>>>
>>> >> > }
>>>
>>> >> > also, if you are just matching against the id, you could just write it
>>> >> > as:
>>>
>>> >> > $post = $this->Post->read(null, $var);
>>> >> > $post['Post']['options'] = value1;
>>> >> > $this->Post->save($post);
>>>
>>> >> > and forget about the loop
>>>
>>> >> > On Aug 20, 3:26 pm, AD7six <andydawso...@gmail.com> wrote:
>>>
>>> >> > > On 20 ago, 15:39, albe <radialremo...@gmail.com> wrote:
>>>
>>> >> > > > I have to make a foreach cycle to check every item of a certain
>>> >> > > > group.
>>> >> > > > For each and every item I've got to check a condition and make a
>>> >> > > > data
>>> >> > > > modification depending on this condition.
>>> >> > > > My code is the following:
>>>
>>> >> > > > foreach($posts as $p) {
>>>
>>> >> > > > $this->Post->id = $p['Post']['id']; //consider the posts
>>> >> > > > one
>>> >> > > > by one
>>>
>>> >> > > > if ($this->Post->id == $var) {
>>> >> > > > $this->data['Post']['options'] = value1;
>>> >> > > > } else {
>>> >> > > > $this->data['Post']['options'] = value 2;
>>> >> > > > }
>>>
>>> >> > > > $this->Post->save($this->data);
>>>
>>> >> > > > }
>>>
>>> >> > > > Here is my problem: the modifications are performed correctly for
>>> >> > > > the
>>> >> > > > IF branch, but NEVER for the else branch.
>>> >> > > > Do you know why this occurs?
>>>
>>> >> > > aliens?
>> >>
>>
>
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