On 25 Set, 12:47, "rich...@home" <richardath...@gmail.com> wrote: > No, you only want to translate the label, not the field name : > > echo $form->input("field_name", array("label"=>__("field_name")));
I tried what you suggested but the result is not what I espected. 1st attempt: echo $form->input('table_id', array('label' => __('table_id'))); The output is: table_id Table that is a label and the name of the joined table. Unfortunately I want just one label, Table, translated if there's a translation. 2nd attempt: echo $form->input('table_id', array('label' => __('table_id', True))); The output is: table_id I expected: Table I'm missing something? I'm expecting too much from cake? Thank you maxx --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---