on your action controller you can put this conditional
if ($this->RequestHandler->isAjax()) {}
in view you need consider this,
on ajax development you still need consider about graceful degradation, so
in every link there must consider if the javascript is not working.
<a href="http://www.xxx.com"; onClick="request.open('http://www.xxx.com";);return
false" />
on default, javascipt will be executed but the link is still work in classic
way.
On Fri, Dec 11, 2009 at 11:16 AM, Jeremy Burns <jeremybu...@me.com> wrote:
> Thank you - I don't suppose you have a simple example do you?
>
> On Dec 11, 4:12 am, "Dr. Loboto" <drlob...@gmail.com> wrote:
> > Pass one URL to AJAX link as link url and other to it's options as
> > AJAX action param.
> >
> > On Dec 10, 11:37 pm, Jeremy Burns <jeremybu...@me.com> wrote:
> >
> >
> >
> > > Thank you, but that isn't working for me. I have a link that retrieves
> > > some data and populates a div with an element. With Javascript
> > > disabled I just get the contents of the element in an otherwise blank
> > > screen. What I want to do is something like this:
> >
> > > If (javascript is enabled):
> > > show this link
> > > else
> > > show another link
> > > end if
> >
> > > So what I am looking for is a nifty little piece of code to do the "if
> > > javascript is enabled" bit.
> >
> > > On Dec 10, 5:27 pm, "Dr. Loboto" <drlob...@gmail.com> wrote:
> >
> > > > AJAX links and forms in Cake AJAX helper has fallback. If JS is not
> > > > enabled links/forms will work as normal ones.
> >
> > > > On Dec 10, 6:58 pm, Jeremy Burns <jeremybu...@me.com> wrote:
> >
> > > > > I want to use the Ajax helper when Javascript is enabled, but
> revert
> > > > > to the plain old ordinary html helper when it is not. How can I do
> a
> > > > > simple test to see if Javascript is enabled?
>
> Check out the new CakePHP Questions site http://cakeqs.org and help others
> with their CakePHP related questions.
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--
Mukhamad Ikhsan
Y!id:ikhsan.only
http://www.diodachi.com
Check out the new CakePHP Questions site http://cakeqs.org and help others with
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