Ok, if you accept using two finds, then you can do it with CakePHP
find types.
[code]
$offer_locations = $this->Offer->find(
'list', array(
'fields' => array(
'id',
'location_id'
),
'conditions' => array(
'Offer.category_id' => $id
)
)
);
$locations = $this->Location->find(
'all', array(
'contain' => array(
'Offer',
'LocationsPicture'
),
'conditions' => array(
'Location.id' => $offer_locations
)
)
);
[/code]
That will give the same result as yours. By passing the result of the
find('list'), which is an array, to the conditions in the find('all'),
CakePHP will automatically assume that IN is wanted for the
Location.id condition.
Hope you find this helpful, and congratulation with you success :)
Enjoy,
John
On Jun 13, 4:24 pm, viciat <viciuasc...@yahoo.com> wrote:
> Solution
> After reading
> this:http://bakery.cakephp.org/articles/view/get-the-find-query-sql-rather...
>
> First get the id's of the locations from the offers corresponding to a
> certain category
>
> $this->Offer->recursive = 0;
> $options = array(
> 'conditions' => array(
> 'Offer.category_id' => $id),
> 'fields' => 'Offer.location_id',
> 'recursive' => -1
> );
> $location_ids =
> $this->Offer->find("sql",$options);
>
> Than get the actual locations
> $location_options = array(
> 'conditions' => array(
> 'Location.id IN ('.$location_ids.')'
> ),
> 'contain' =>
> array('Offer','LocationsPicture')
> );
>
> $locations = $this->Location->find('all',
> $location_options);
> $this->set('locations',$locations);
> --
> View this message in
> context:http://old.nabble.com/3-models-and-search-condition-tp28866040p288712...
> Sent from the CakePHP mailing list archive at Nabble.com.
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