Are you familiar with type-conv and the family of syntax-extensions that go
along with it? You can do thinks like:
type t = { foo: int; bar: string }
with sexp, compare, bin_io
and automatically get sexp-conversion functions, a comparison function, and
binary protocol converters. And type-conv has been used to build other
type-directed functions by other people outside of Jane Street.
The latest version is available on bitbucket, and we'll have a new blessed
release in a few days.
https://bitbucket.org/yminsky/ocaml-core/
Note that this is done purely syntactically, and yet gets you there.
y
On Wed, Mar 7, 2012 at 6:49 AM, Matej Košík <
5764c029b688c1c0d24a2e97cd7...@gmail.com> wrote:
> Hi,
>
> I would like to print out the response of a modified Ocaml's typechecker
> to various inputs.
>
> One way to do it would be to write a pretty-printer by hand.
>
> Before I do that, I would like to apply "deriving" machinery:
> http://code.google.com/p/deriving/wiki/Introduction
> to this (chore) job.
>
> In some cases I do not know what to do.
>
> E.g., file "types/types.mli" contains the following definition:
>
> and value_kind =
> Val_reg
> | Val_prim of Primitive.description
> | Val_ivar of mutable_flag * string
> | Val_self of
> (Ident.t * type_expr) Meths.t ref *
> (Ident.t * mutable_flag * virtual_flag * type_expr) Vars.t ref *
> string * type_expr
> | Val_anc of (string * Ident.t) list * string
> | Val_unbound
>
> If I add
>
> deriving (Show)
>
> at the end of the above definition, I get an error:
>
> Error: Unbound module Meths.Show_t
>
> That is expected but I am not sure what to do. That is, I am not sure
> what is the official way to "deriving"-sify the "Meth" module which
> defined in the following way:
>
> module Meths = Map.Make(OrderedString)
>
> without the need to modify files "map.ml{i,}".
>
> Is something like that possible?
>
> Thank you very much in advance for any help.
>
> --
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>
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