You need parenthesis around (n+1), and it's "if m>first(element ) && n< second(element)" : "and" is an OCaml keyword.
There is a beginner list ( http://groups.yahoo.com/group/ocaml_beginners ) that would probably be more suited to those questions. On 2/22/09, Su Zhang <westlif...@gmail.com> wrote: > Hi all, > > I have a problem while executing ocaml, did you see any problem in my code? > and do I need to give each variable a type before I use it ?my code is in > the following, you can take a look at the code and the info of the errors > > > let rec first(x, y, z)=x > > let rec second(x,y,z)=y > > let rec third(x,y,z)=z > > > > let rec rebuilt anss (m,n,ys)= match anss with > > [] -> (m,n,ys) > > |element::anss -> > > if m>first(element ) and n< second(element) > > then rebuilt anss (m,n,ys) > > else element::(rebuild anss (m,n,ys)) > > > > let rec sum anss cur n ys= match cur with > > None -> > > (match ys with > > []-> anss > > |y::ys-> > > if y=0 > > then sum(rebuild anss (n,n,0)) None n+1 ys > > else sum anss (Some(n, y, [y])) (n + 1) ys) > > > the red area is shown has an error, and the error info is like this:"This > expression has type int list -> 'a but is here used with type int", so would > you please let me know if possible how can I let the compiler know the type > of anss is a list but not an integrer? > > thank you > -- > Su Zhang > PHD Student > Computer Information and Science > Kansas State University > _______________________________________________ Caml-list mailing list. Subscription management: http://yquem.inria.fr/cgi-bin/mailman/listinfo/caml-list Archives: http://caml.inria.fr Beginner's list: http://groups.yahoo.com/group/ocaml_beginners Bug reports: http://caml.inria.fr/bin/caml-bugs
