> #include<stdio.h>
>
> int i=2;
> void main()
> {
> int i=3;
> {
> int i=10;
> {
> int i=5;
> {
> printf();
> }
> }
> }
> }
>
>what can i write in printf so that the output will give the value of
>i=3;
> VIVEK
If it is C++ you can use scope resolution operator and print 2
by printing ::i, without scope resolution it will print 5.
If you want to print only three then may be you can do this
printf("%d",i=3);
It will assign value 3 to ur last defined i=5 and will print.
(i think u forgot to write int before i=10 and i=5 )
if it is C program u can access only local variable (inner most/near most local tp
printf , plz correct me if i ma wrong )
if it is C++ you can access local (inner most) variable as well as global variable
using ::operator.
I dont think there is any other ways to access other local variable
which have the same name as the inner most local variable.
plz correct me if i am wrong.
-Arif
------------------------ Yahoo! Groups Sponsor --------------------~-->
Make a clean sweep of pop-up ads. Yahoo! Companion Toolbar.
Now with Pop-Up Blocker. Get it for free!
http://us.click.yahoo.com/L5YrjA/eSIIAA/yQLSAA/EbFolB/TM
--------------------------------------------------------------------~->
To unsubscribe : [EMAIL PROTECTED]
Yahoo! Groups Links
<*> To reply to this message, go to:
http://groups.yahoo.com/group/Programmers-Town/post?act=reply&messageNum=3654
Please do not reply to this message via email. More information here:
http://help.yahoo.com/help/us/groups/messages/messages-23.html
<*> To visit your group on the web, go to:
http://groups.yahoo.com/group/Programmers-Town/
<*> To unsubscribe from this group, send an email to:
[EMAIL PROTECTED]
<*> Your use of Yahoo! Groups is subject to:
http://docs.yahoo.com/info/terms/
