erudeuin wrote:
> template <class _tipe>
> class Item
> {
> public:
> Item() {
> mpData = NULL;
> }
>
> Item &operator=(const _tipe &rNewData) { //FIXME!!!
> setData(rNewData);
> return *this;
> }
If you write Item operator=(const _tipe &rNewData), a copy is returned
instead of a reference. Because you defined no copy constructor, the
default copy constructor is used, which simply copies the memory that
the object uses. So a new Item<int> object is returned, with the same
pointer. Because you don't use the return value, it is deleted
immediately, so the destructor deletes the pointer. But your object 'a'
has the same pointer, so that is deleted, and probably set to 0 by your
compiler.
It is best to always return a reference. It is safer and faster.
> [...]
> is that my code above safe(especially memory leak)
> could i assign int value for 'a object' repeatedly, for instance
> a = 5;
> a = 6; //and etc, will it be memory leak
I tried it in MSVC++, which has good memory leak detection, and it
detected no memory leaks, even with the extra a=5 and a=6.
--
Mark Van Peteghem
http://www.q-mentum.com -- easier and more powerful unit testing
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