Hi, I am stuck on *cas.authn.jdbc.encode*, although I can get *cas.authn.jdbc.query* to work OK.
cas.authn.jdbc.encode throws "*Authentication handler is not configured correctly*", maybe is due to (StringUtils.isBlank(this.sql) || StringUtils.isBlank(this.algorithmName) || getJdbcTemplate() == null) ?? *** Environment *** - CAS Version: 5.2.0-RC4-SNAPSHOT - Java Version: 1.8.0_131 - Apache Tomcat Version: Apache Tomcat/8.0.32 (Ubuntu) - Linux Ubuntu Xenial Version: 16.04.3 *** pom.xlm ** *Only relevant changes are: <cas.version>5.2.0-RC4-SNAPSHOT</cas.version> ...and... <dependency> <groupId>org.apereo.cas</groupId> <artifactId>cas-server-support-jdbc</artifactId> <version>${cas.version}</version> </dependency> <dependency> <groupId>org.apereo.cas</groupId> <artifactId>cas-server-support-jdbc-drivers</artifactId> <version>${cas.version}</version> </dependency> *** cas.properties *** Note first, that the following works fine - note the clever trick with *fieldPassword=username*: cas.authn.jdbc.query[0].url=jdbc:mysql: //lxc-mysql.home:3306/guacamole_db?useSSL=false cas.authn.jdbc.query[0].driverClass=com.mysql.cj.jdbc.Driver cas.authn.jdbc.query[0].user=guac_username cas.authn.jdbc.query[0].password=guac_password cas.authn.jdbc.query[0].sql=SELECT * FROM guacamole_user WHERE username=? cas.authn.jdbc.query[0].fieldPassword=username However, the following does not work (FWIW, this <https://guacamole.incubator.apache.org/doc/gug/jdbc-auth.html> may be a useful reference): cas.authn.jdbc.encode[0].url=jdbc:mysql: //lxc-mysql.home:3306/guacamole_db?useSSL=false cas.authn.jdbc.encode[0].driverClass=com.mysql.cj.jdbc.Driver cas.authn.jdbc.encode[0].dialect=org.hibernate.dialect.MySQL5Dialect cas.authn.jdbc.encode[0].user=guac_username cas.authn.jdbc.encode[0].password=guac_password cas.authn.jdbc.encode[0].sql=SELECT * FROM guacamole_user WHERE username=? cas.authn.jdbc.encode[0].disabledFieldName=disabled cas.authn.jdbc.encode[0].saltFieldName=password_salt cas.authn.jdbc.encode[0].passwordFieldName=password_hash cas.authn.jdbc.encode[0].passwordEncoder.type=DEFAULT cas.authn.jdbc.encode[0].passwordEncoder.characterEncoding=UTF-8 cas.authn.jdbc.encode[0].passwordEncoder.encodingAlgorithm=SHA-256 Which throws this error: 2017-09-23 23:20:06,446 DEBUG [org.apereo.cas.authentication. PolicyBasedAuthenticationManager] - <[ QueryAndEncodeDatabaseAuthenticationHandler] exception details: [ Authentication handler is not configured correctly].> I see from QueryAndEncodeDatabaseAuthenticationHandler.java <https://github.com/apereo/cas/blob/master/support/cas-server-support-jdbc-authentication/src/main/java/org/apereo/cas/adaptors/jdbc/QueryAndEncodeDatabaseAuthenticationHandler.java> that: if (StringUtils.isBlank(this.sql) || StringUtils.isBlank(this.algorithmName ) || getJdbcTemplate() == null) { throw new GeneralSecurityException("Authentication handler is not configured correctly"); } Can anyone suggest a solution, or (heaven forbid) is it a bug? -- - Website: https://apereo.github.io/cas - Gitter Chatroom: https://gitter.im/apereo/cas - List Guidelines: https://goo.gl/1VRrw7 - Contributions: https://goo.gl/mh7qDG --- You received this message because you are subscribed to the Google Groups "CAS Community" group. To unsubscribe from this group and stop receiving emails from it, send an email to cas-user+unsubscr...@apereo.org. To view this discussion on the web visit https://groups.google.com/a/apereo.org/d/msgid/cas-user/b08cb989-21c6-47d5-85c4-38905de43f52%40apereo.org.