Hm, this is one of theses places where it is quite difficult to come
around, without having good knowledge of windsor's internal
workings...
Anyone can give me a a bit more concrete hint, of how I can achieve
the above api?
I think I have two options:
one would be to inject the name of the registration into the service
and return this by a regular ResolveAll() or
I could somehow tell Windsor to pass me the registered services
together with their keys as a dictionary.
but, for now, I have no idea how to implement this...
On Mon, Oct 27, 2008 at 7:45 PM, Jan Limpens <[EMAIL PROTECTED]> wrote:
> I have this situation:
>
>
> public IList<IOrderRule> ResolveAll()
> {
> return kernel.ResolveAll<IOrderRule>();
> }
>
> public IDictionary<string, IOrderRule> ResolveAllWithKey()
> {
> ...?
> }
>
> ISubResolver only has a Resolve() for a single item. How can I come around
> this?
>
>
> On Fri, Oct 24, 2008 at 10:19 PM, Ayende Rahien <[EMAIL PROTECTED]> wrote:
>>
>> You can use a ISubDependencyResolver
>>
>> On 10/25/08, Jan Limpens <[EMAIL PROTECTED]> wrote:
>> > If I register a component like so
>> >
>> > <component id="xxx" type="sometype" service="someservice">
>> > <parameters>
>> > <description>bla</description>
>> > </parameters>
>> > </component>
>> >
>> > and I also want to use the component's id as a parameter without having
>> > to
>> > repeat myself, how could I do that?
>> >
>> > public class sometype : someservice {
>> > public sometype(string id, string description){
>> > ...
>> > }
>> > }
>> >
>> > --
>> > Jan
>> > ___________________
>> > [EMAIL PROTECTED]
>> > www.limpens.com
>> > +55 (11) 3082-1087
>> > +55 (11) 3097-8339
>> >
>> > >
>> >
>>
>> >>
>
>
>
> --
> Jan
> ___________________
> [EMAIL PROTECTED]
> www.limpens.com
> +55 (11) 3082-1087
> +55 (11) 3097-8339
>
--
Jan
___________________
[EMAIL PROTECTED]
www.limpens.com
+55 (11) 3082-1087
+55 (11) 3097-8339
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