Re: ExpressionFactory.matchAllExp(...)

[Marcel]

Thanks. As an API comment consider that in:
   public static Expression *matchExp*(String pathSpec, Object value)

'match' implies the use of equals. My mistake was moving from matchExp 
to matchAllExp.

Marcel

Andrus Adamchik wrote:
   Expression qual = ExpressionFactory.matchAllExp(map, Expression.AND);

This line should look like:

   Expression qual = ExpressionFactory.matchAllExp(map, 
Expression.EQUAL_TO);

I.e. the last parameter refers to the operation inside each key/value 
pair.

Andrus

On Jul 25, 2006, at 1:36 AM, Marcel wrote:
Andrus,

Sorry, it came out unclearly in the email. The exception, an 
ExpressionException, doesn't have a stack trace.

Here is a standalone snippet that will create the problem:

private void matchAllTest() {
   HashMap map = new HashMap();
   map.put("test", "test");
   Expression qual = ExpressionFactory.matchAllExp(map, Expression.AND);
}