The same way we do this in IPv4... Binary. :) 2020:100:100:2220::/64 2020:100:100:2200::/64
The difference is in the third word. 2200 vs 2220. In binary: 0010 0010 0000 0000 0010 0010 0010 0000 Since we are summarizing, we have to come up with a value that represents both values. So the difference is in the 6th position from the right side. If we start with a /64 and slide that "mask" bar 6 more positions to the left (64 - 8) we get a /58 that will cover both. HTH, Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE #153, CISSP, et al. CCSI/JNCI-M/JNCI-J IPExpert VP - Curriculum Development IPExpert Sr. Technical Instructor [EMAIL PROTECTED] http://www.ipexpert.com -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Andrea Riela Sent: Tuesday, July 18, 2006 11:35 AM To: [email protected] Subject: [OSL | CCIE_RS] WB 8.0 Section 11 task 5 - ospf area range (ipv6) -----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi folks, I don't know how to summmarize two ipv6 addresses for ospf area range. The two addresses are: 2020:100:100:2220::/64 2020:100:100:2200::/64 the answer is '2020:100:100:2200::/58', but why? Could you explain that? please help me Regards Andrea -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.1 (Darwin) iD8DBQFEvP+OMakHrsrHP9wRAtXXAJsGQX6DFrFEN+76i+Ik4FH5FAz6aQCdGfK9 figD1NNyS91aRBijYaoPJ4Q= =9wfR -----END PGP SIGNATURE-----
