Because 192.1.1.0 would set your initial starting bits. Once you put your "starting point" in place and then apply a mask (which tells you which bits can change and which ones cannot) then the results you get will be different! HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE-M #153, JNCIS-ER, CISSP, et al. CCSI/JNCI-M/JNCI-ER VP - Technical Training - IPexpert, Inc. IPexpert Sr. Technical Instructor A Cisco Learning Partner - We Accept Learning Credits! [EMAIL PROTECTED] Telephone: +1.810.326.1444 Fax: +1.810.454.0130 http://www.ipexpert.com _____ From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of GAURAV MADAN Sent: Saturday, January 26, 2008 12:39 PM To: Ralph Olsen Cc: [email protected] Subject: Re: [OSL | CCIE_RS] Wildcard Q Hi Perfect explanation . We want 192.1.1.1 192.1.3.1 192.1.5.1 192.1.7.1 192.1.9.1 This will make 192.1.1.1 0.0.14.0 . Which is why we write access-list 1 permit 192.1.1.1 0.0.14.0 Can any one comment on why they have written 192.1.1.0 0.0.14.0 instead of 192.1.1.1 0.0.14.0 Gaurav Madan. On 1/26/08, Ralph Olsen <[EMAIL PROTECTED]> wrote: Hi Khalid, You don't care about the 1st, 2nd and 4th octet, because that will be 0 as it doesn't change. You will have the 3rd octet being 1 3 5 7 9 If you write that in binary you will get 1 00000001 3 00000011 5 00000101 7 00000111 9 00001001 So in the wildcard mask we know that a fixed bit will be marked as a 0 and a wildcard bit will be marked as a 1. 1 00000001 3 00000011 5 00000101 7 00000111 9 00001001 00001110 <-- Bit 5,6,7 (from left to right) is wildcard bits. And converting 00001110 to decimal will give you 14. The wildcard mask being 0.0.14.0. Hint: Use Windows notepad and calculator and write all IP address' in binary. That will give you a better visual overview. /Ralph Olsen > Hi all, > > we have 2 routers R1.......> R2 and R1 has 10 Lo interfaces: > Lo1: 192.1.1.1/24 <http://192.1.1.1/24> > Lo2: 192.1.2.1/24 <http://192.1.2.1/24> > Lo3L 192.1.3.1/24 <http://192.1.3.1/24> upto 192.1.10.1/24 > <http://192.1.10.1/24> > > we need to configure R2 to ONLY receive the odd addresses from R1 > > the answer was: > > R2: > access-list 1 permit 192.1.1.0 <http://192.1.1.0> 0.0.14.0 > <http://0.0.14.0> > router rip > distance 255 150.50.17.1 <http://150.50.17.1> 255.255.255.255 > <http://255.255.255.255> 1 > Note: 150.50.17.1 <http://150.50.17.1> is R1 > this Q is from the workbook. Can you give me a full explanation > about 0.0.14.0 <http://0.0.14.0> > > thnx
