I always had trouble with these. Would take me 30 min to figure out each one. I went to the Ipexpert boot camp and Jared showed us how to do them in your head in about 30 seconds.
From: ccie_rs-boun...@onlinestudylist.com [mailto:ccie_rs-boun...@onlinestudylist.com] On Behalf Of prakash patel Sent: Monday, May 18, 2009 10:00 AM To: antonio_...@hotmail.com; ccie_rs@onlinestudylist.com Subject: Re: [OSL | CCIE_RS] ACL filtering blues Hello 10=00001010 13=00001101 14=00001110 What is the common here ?....00001xxx so xxx vlaues give you 0.0.7.0 the fist should be 10.10.8.0 so the whole completed is 10.10.8.0 0.0.7.0 if u see logical in 3rd octets ...8 is starting value and ending 8+7 = 15 10.10.8.0 thru 10.10.15.0 makes sense? ________________________________ From: antonio_...@hotmail.com To: ccie_rs@onlinestudylist.com Date: Mon, 18 May 2009 23:23:05 +0930 Subject: [OSL | CCIE_RS] ACL filtering blues Hi All, Need some help on ACL calculation. This is general ACL filtering scenario. I'm just practicing on ACL filtering especially on the non-continuous wildcards. i've injected this to my test router but i don't seem to get the logic why it's this wildcard. can somebody enlighten me on this? I know 0 in the wildcard are care bits and 1 don't care, just the opposite of a subnet mask. Example Scenario: I get this networks from a backbone router: network 10.10.10.0 network 10.10.11.0 network 10.10.12.0 network 10.10.13.0 network 10.10.14.0 network 10.10.15.0 network 10.10.16.0 I want to filter on the third octet and allow only 10, 13, 14 to come in been playing with various values on the wildcard, and the working value is 0.0.4.0 , WHY???? Kind Regards, Antonio ________________________________ Windows Live(tm): Keep your life in sync. Check it out.<http://windowslive.com/explore?ocid=TXT_TAGLM_BR_life_in_synch_052009>
