OK, here is my response, to Marko's mini-task.... Already specified groups: > > 226.0.0.0/7 > 229.0.0.0/8 > I was thinking that for these (two examples) it would be on R4: > 229.0.x.x/ wild card 0.0.255.255 and 226.0.0.0 0.0.255.255 > Here I am interpreting as "second half of octets of already specified > addresses". > > ======== > alternate logic > 224-239 (first MCAST Octet) = 16 first octet options and half of that is 8 > > first half: 224,225,226,227,228,229,230,231 > > second half: 232,233,234,235,236,237,238,239 > group-list (acl): 232.0.0.0 7.255.255.255 > > this is the interpretation of the solution.
> :-) > > I guess if I wrote it out like that the proctor would be happy to clear > things up. It shows I know what I am talking about just confused about > syntax. > > thanks for the help Marko (with a K). ;-) >
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