*4 is approximate.  I would stick with the first.

Access Rate (AR) = Bc + Be

 

Regards,

 

Tyson Scott - CCIE #13513 R&S, Security, and SP

Managing Partner / Sr. Instructor - IPexpert, Inc.

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From: [email protected]
[mailto:[email protected]] On Behalf Of Roy Shaver
Sent: Monday, August 16, 2010 7:03 PM
To: [email protected]
Subject: [OSL | CCIE_RS] FR Traffic Shaping Clarification

 

I understand Tc=Bc/CIR which makes perfect sense.  I have found in my
studies that confuse what Be should be.  For example if I have a 64k CIR and
am allowed to burst to 256k and you need to set the configuration such that
Tc equals 200ms or 1/5Sec.  And as I understand Bc + Be = Burst then the
math should be as follows:

Tc = Bc / CIR
CIR = 64000
Tc = 200ms or 1/5
Bc = 64000/5 = 12800

So all straight forward so far... Now to figure Be.

(Bc + Be) * 5 = 256000
(12800 + Be) * 5 = 256000

Some math I couldn't figure out how to write in the e-mail....

Be = 38400

Thus

(12800 + 38400) * 5 = 256000


Now here is were the confusion sets in.... Some examples I have read and
seen people are saying since 256k is 4 time 64k then multiply Bc times 4 and
you have Be.  But when I do that the math works out that you would be
bursting to  320k not 256k.

(12800 + 51200) * 5 = 320000

So the question is, Do you add Bc to Be to calculate the burst or do you do
as some of the examples I have seen do and multiple it by whatever.

I was sure I was doing it right until I saw some examples do it differently.

Thanks,

Roy S. 

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