If you want to match only 3 and 5 then it would be 192.168.3.0 0.0.6.255 right ? You would also match 192.168.1.1 with the wildcard mask that you provide right ?
Can someome confirm this and share their experience about it ? Much appreciated Aung. Nic 2010/11/25 Aung Phyo Lwin <[email protected]> > > For me, I'm using binary method AND/OR between address list. AND is address > to match and OR is wildcard. But sometime, I'm still having problem and > still not fast enough to calculate. > General wildcard are ok. Just minus from 255. 255.255.255.240 mask is > 255-240 = 15 , 0.0.0.15 > For specific wildcard, I calculate like this. > > 192.168.2.1 > 192.168.3.1 > 192.168.4.1 > 192.168.5.1 > I want to match 3rd Octet, only .3 and .5 > > 3rd Octet > 2/ 00000010 > 3/ 00000011 > 4/ 00000100 > 5/ 00000101 > > then > 3/ 00000011 > 5/ 00000101 > AND 00000001 - 1 > OR 00000110 - 6 > > So the address is 192.168.1.0 > wildcard is 0.0.6.0 > > For .2 and .4, 192.168.0.0 and wildcard 0.0.6.0 > > Pls share me if you guys have other method to calculate faster. Thanks. > > Regards, > Phyo > > ------------------------------ > *From:* Nicolas MICHEL <[email protected]> > *To:* OSL Routing and Switching <[email protected]> > *Sent:* Thursday, November 25, 2010 17:55:45 > *Subject:* [OSL | CCIE_RS] Wildcard Mask > > Hey guys, > > I'm in trouble with Wildcard mask. I know that 0 is a match and 1 is a dont > care but I have trouble to calculate that since I did calculate all my Masks > using a decimal technique. > > If someone could clarify with exemples etc etc I would be so thankfull ! > > -- > Nicolas MICHEL > Ingenieur Réseaux et Securité (CCNA/CCNP) > > > > > > -- Nicolas MICHEL Ingenieur Réseaux et Securité (CCNA/CCNP)
_______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com
