Hi Marko,

;-) sorry about that, i'll try to clarify
Well in the video for 24.5 (25.6 actually) Volume 1, it is a question to 
advertise R9 as the RP for 228 and 230, in the minimum amount of lines. And Joe 
states that you cannot use the 2.255.255.255 mask to encompass both 228 and 
230, as you normally would in a acl to complement the auto-rp command with. He 
says it would translate into both /8 being advertised as /7? 
He says if i want to know why i should do a debug ip pim, i had not labbed it 
up yet, i just wondered the reason why that behaviour would occur and if it 
only would happen for this specific acl line. It seems strange to me, but 
according to him it cannot be done so we need two lines advertising both 
networks out as /8.

As in :
ip pim send-rp-announce lo2 scope 10 group-list 101

where acl 101 would have a line of permit 228.0.0.0 2.255.255.255

So the catch here seems to be the minimum amount of lines is 2 instead of 1

On Jun 21, 2011, at 9:11 PM, Marko Milivojevic wrote:

> I have re-read your question at least 5 times now and I must say I'm a
> bit lost ... :-(
> 
> What exactly are you trying to do? Could you clarify a little bit?
> 
> --
> Marko Milivojevic - CCIE #18427
> Senior Technical Instructor - IPexpert
> 
> FREE CCIE training: http://bit.ly/vLecture
> 
> Mailto: [email protected]
> Telephone: +1.810.326.1444
> Web: http://www.ipexpert.com/
> 
> On Tue, Jun 21, 2011 at 06:22, Alef <[email protected]> wrote:
>> Hi,
>> Why doesn't auto-rp handle 2.255.255.255 properly for encompassing 
>> 228.0.0.0/8 and 230.0.0.0/8 ? it advertises out 228 /7 and 229 /7 ?
>> is this behaviour only with this mask specifically, as other wildcards don't 
>> seem to be a problem?
>> 
>> alef
>> 
>> 
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