Can anyone confirm that if i want to include both 10.0.1.4 and 200.0.3.0 in a single statement, that i would have to use a wildcard mask of 194.0.2.4 ?
this would allow for 5 bits difference in total, 32 networks and the following octet possibilities [0,2,8,64,128,192,200,202]][0][1,3][4,0] 0.0.1.4 64.0.1.4 200.0.1.4 0.0.1.0 64.0.1.0 200.0.1.0 0.0.3.4 64.0.3.4 200.0.3.4 0.0.3.0 64.0.3.0 200.0.3.0 2.0.1.4 128.0.1.4 202.0.1.4 2.0.1.0 128.0.1.0 202.0.1.0 2.0.3.4 128.0.3.4 202.0.3.4 2.0.3.0 128.0.3.0 202.0.3.0 8.0.1.4 192.0.1.4 8.0.1.0 192.0.1.0 8.0.3.4 192.0.3.4 8.0.3.0 192.0.3.0 _______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com Are you a CCNP or CCIE and looking for a job? Check out www.PlatinumPlacement.com
