To get only 16bit private ASs (so this regex won't work with 32bit private ASs), I would rather use this one:
(6451[2-9]|645[2-9][0-9]|64[6-9][0-9][0-9]|65([0-4][0-9][0-9])|(5([0-2][0-9])|(53[0-5])) -- Marko Milivojevic - CCIE #18427 (SP R&S) Senior Technical Instructor - IPexpert On Tue, Oct 25, 2011 at 22:03, imad Abdallah <[email protected]> wrote: > > Throughout the WBs they've been using the following AS-Path filter to select > private AS numbers: > 64[5-9][0-9][0-9]|65[0-5][0-9][0-9] > Is this correct?As per my understanding the above filter will also > match:64500, 64501..... And those are not part of the private ASs which start > at 6451265540-->65599. Also outside the private AS numbers; as the last > private AS is 65534 > Can somebody please correct me if i'm wrong. And if not, what is the quickest > and easiest way to select private ASs > > _______________________________________________ > For more information regarding industry leading CCIE Lab training, please > visit www.ipexpert.com > > Are you a CCNP or CCIE and looking for a job? Check out > www.PlatinumPlacement.com > _______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com Are you a CCNP or CCIE and looking for a job? Check out www.PlatinumPlacement.com
