Sending this mail again as an attached word document to protect the format.
-RS
I was working on to get a network and wildcard for the below mentioned networks
and I got this answer --> 192.49.166.0 4.255.1.255 which is untrue! The correct
answer is 205.49.166.0 2.0.1.255
http://blog.ipexpert.com/2009/06/10/wild-card-masks/
205.49.166.0/24
207.49.166.0/24
208.49.166.0/24
205.49.167.0/24
207.49.167.0/24
192.49.166.0/24
I'm writing the process I am following to do the ANDing and XORing operations
of these networks, I'll take the first octet of all the networks.
First the AND operations
208 -> 1 1 0 0 1 1 0 1 208 -> 1 1 0 0 1 1 0 1 207 ->
1 1 0 0 0 1 1 1
207 -> 1 1 0 0 0 1 1 1205 -> 1 1 0 0 0 1 0 1 192 -> 1 1 0 0 0 0 0 0
----------------------------------------------------------------
--------------------------------------
AND->1 1 0 0 0 1 0 1 -> 208AND->1 1 0 0 0 1 0 1 ->208AND-> 1 1 0 0 0 0 0 0 ->
192
Now I am ANDing the results of first two and the result of this I'll AND with
the result of third AND operation done above which is 192.
208 -> 1 1 0 0 0 1 0 1196-> 1 1 0 0 0 1 0 0
208-> 1 1 0 0 0 1 0 0192-> 1 1 0 0 0 0 0 0
-----------------------------------------------------------------
AND-> 1 1 0 0 0 1 0 0 -> 196AND->1 1 0 0 0 0 0 0 -> 192-> And hence the first
octet of the network would be 192!
Now the XOR operations.
208 -> 1 1 0 0 1 1 0 1 208 -> 1 1 0 0 1 1 0 1 207 ->
1 1 0 0 0 1 1 1
207 -> 1 1 0 0 0 1 1 1205 -> 1 1 0 0 0 1 0 1 192 -> 1 1 0 0 0 0 0 0
---------------------------------------------------------------- --------------------------------------
XOR-> 0 0 0 0 1 0 1 0 ->10 AND-> 0 0 0 0 1 0 0 1 ->9AND-> 0 0 0 0 0 1 1 1 -> 7
Now I am XORing the results of first two and the result of this I'll XOR with
the result of third XOR operation done above which is 7.
10 -> 0 0 0 0 1 0 1 0 3-> 0 0 0 0 0 0 1 1
9-> 0 0 0 0 1 0 0 1 7-> 0 0 0 0 0 1 1 1
-----------------------------------------------------------------
XOR->0 0 0 0 0 0 1 1 -> 3 AND->0 0 0 0 0 1 0 0 -> 4 -> And hence the first
octet of the wildcard mask would be 4!
So the first Octet of Network statement I get is 192 and the first octet of
wildcard mask I get is 4!
>>> The other question I have is about the wild card mask, in the answer it is
>>> 2.0.1.255, here the second octet which has all zeros is written as a Zero
>>> "0" rightly, but the last octet which is also all zeros is written as 255?
>>> I found this a rather strange phenomenon!!
While I am sure I am doing the AND and XOR operations correctly, I might
be inadvertently deviating somewhere during the calculation!
Requesting comments from all the experts in this forum.
-RS
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