I see a loop..

On Fri, Aug 10, 2012 at 8:20 AM, Bob McCouch <[email protected]> wrote:

> Hi Fulvio,
>
> I think your confusion comes from the usual split-horizon definition
> that "a route is never advertised out an interface it is learned
> from," but that's an incomplete definition. Split-horizon comes into
> play when the *best* route is learned from an interface, in which case
> it will not be sent back out that same interface. Since R1 & R2 in
> your example would each have their best path (successor route) through
> their "other" interface, they would both advertise a path onto the
> common segment for R1-4. R3 & R4 would learn equal-cost routes via
> both 1 & 2.
>
> Hope that helps,
> Bob
>
> Sent from my iPad
>
> On Aug 9, 2012, at 10:55 AM, Fulvio allegretti <[email protected]>
> wrote:
>
> > Right, I know the best thing to do here would be to lab this and I will,
> promise, but I'd like to know your understanding on this and if it is
> something to worry about.
> > Let's say we have 4 routers on a LAN all talking eigrp. Two of these
> routers, router 1 and 2, have an eigrp path to subnet 1.1.1.0/24somewhere 
> else  thorugh an interface  not on the LAN and lets's assume for
> sake of argument that the metric to 1.1.1.0/24 is the same for both of
> them. Considering split-horizon there will be only one router, 1 or 2,
> injecting that route on the LAN, right? One of the two routers will have
> its best path to 1.1.1.0/24 through its own interface but won't inject it
> on the lan as it heard it  injected on the LAN from the other one.
> > 1) What decides which one of the two will inject the route on LAN? Is it
> the first router timewise that injects it on the LAN?
> > 2) Let's assume R1 did, what happens if the metric through R2
> "improves", would the LAN routers choose the path through R2 now?
> > Fulvio
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