Dear All The following is part of a pdb file for a protein containing two galactose molecules. In this form programs like Accelerys using the Hierarchy facility selects the two galactoses in the same operation. Does anyone know how they could be labelled so that they can be selected individually? I want to inspect the individual binding sites. Thanks Rex Palmer Birkbeck College HETATM 3993 C1 GAL B 265 -3.839 64.712 -19.974 1.00 66.90 C HETATM 3994 C2 GAL B 265 -4.291 64.321 -18.565 1.00 65.48 C HETATM 3995 C3 GAL B 265 -4.084 62.837 -18.359 1.00 63.84 C HETATM 3996 C4 GAL B 265 -4.785 62.055 -19.458 1.00 63.79 C HETATM 3997 C5 GAL B 265 -4.300 62.534 -20.823 1.00 64.83 C HETATM 3998 C6 GAL B 265 -4.978 61.844 -21.998 1.00 65.56 C HETATM 3999 O1 GAL B 265 -4.097 66.059 -20.205 1.00 69.47 O HETATM 4000 O2 GAL B 265 -3.553 65.044 -17.589 1.00 64.26 O HETATM 4001 O3 GAL B 265 -4.623 62.490 -17.107 1.00 63.63 O HETATM 4002 O4 GAL B 265 -6.178 62.270 -19.357 1.00 63.36 O HETATM 4003 O5 GAL B 265 -4.553 63.942 -20.955 1.00 66.42 O HETATM 4004 O6 GAL B 265 -4.977 62.654 -23.172 1.00 65.19 O HETATM 4005 C1 GAL B 267 1.446 15.293 -5.065 1.00 65.53 C HETATM 4006 C2 GAL B 267 1.023 16.517 -4.222 1.00 65.44 C HETATM 4007 C3 GAL B 267 0.004 17.403 -4.937 1.00 64.48 C HETATM 4008 C4 GAL B 267 0.479 17.680 -6.339 1.00 64.32 C HETATM 4009 C5 GAL B 267 0.615 16.360 -7.042 1.00 64.50 C HETATM 4010 C6 GAL B 267 0.917 16.512 -8.523 1.00 65.07 C HETATM 4011 O1 GAL B 267 2.620 14.765 -4.542 1.00 65.62 O HETATM 4012 O2 GAL B 267 0.463 16.077 -2.989 1.00 64.51 O HETATM 4013 O3 GAL B 267 -0.102 18.626 -4.241 1.00 64.73 O HETATM 4014 O4 GAL B 267 1.754 18.287 -6.261 1.00 63.35 O HETATM 4015 O5 GAL B 267 1.703 15.644 -6.439 1.00 65.18 O HETATM 4016 O6 GAL B 267 0.838 15.264 -9.201 1.00 65.27 O
Rex Palmer http://www.bbk.ac.uk/biology/our-staff/emeritus-staff http://rexpalmer2010.homestead.com
