I think Gerard has answered the original question. To introduce additional 
complications (do people want complications?), there is apparently an issue 
with the ease of getting reflections in a powder pattern.  

A new theory for X-ray diffraction
Fewster, P. F. (2014). Acta Cryst. A70, 257-282.
http://journals.iucr.org/a/issues/2014/03/00/sc5066/index.html

A couple of quotes (I don't think they are out of context)
For powder diffraction, this theory " explains why diffraction peaks are 
obtained from samples with very few crystallites, which cannot be explained 
with the conventional theory."
"If the whole diffraction process is considered as an interference problem then 
the contributions are not confined to the Bragg condition."

Colin

-----Original Message-----
From: Gerard Bricogne [mailto:g...@globalphasing.com] 
Sent: 09 July 2014 00:38
To: ccp4bb
Subject: Re: [ccp4bb] question about powder diffraction

Dear all,

     The downstream end of this thread seems to have drifted into learned 
considerations of spelling, so I am getting back to this early reply.

     I am surprised that nobody has mentioned the role of the wavelength in all 
this: there is no way that one can directly link the first four planes in a 
Nickel crystal to a fixed set of 2theta values. The values you quote, Kianoush, 
must have been observed for a certain wavelength, but they would be different 
for another wavelength. So if you want one of the powder rings to come out at a 
2theta of 45 degrees, adjust the wavelength accordingly so that Bragg's law be 
satisfied for the spacing between the corresponding planes.

     There also seems to be a confusion in the last question (unless I have 
completely misunderstood it) about the orientation of a crystal and the Bragg 
angle at which it will contribute to the ring pattern of the powder it belongs 
to. If there is a crystal oriented with some if its planes at 45 degrees from 
the X-ray beam, that will simply determine where on each ring its diffraction 
spots will contribute: it will have no effect on the Bragg angles of those 
spots, that depend purely on the internal spacings between atoms within the 
crystal, not on the orientation of the crystal. At the same wavelength at which 
you quote the 2theta values for those four rings, the crystal at 45 degrees 
from the beam will still have its diffraction spots contribute to the rings at 
44, 52, 76 and 93 degrees.

     Again, forgive me if I have completely misunderstood the initial question.


     With best wishes,
     
          Gerard.

--
On Tue, Jul 08, 2014 at 04:13:59PM -0400, Edward A. Berry wrote:
> The plane will scatter, and all atoms in the plane will scatter in 
> phase if angle of incidence equals angle of reflection. this is how a 
> mirror reflects. Furthermore all the parallel planes will also reflect at 
> this angle.
> Trouble is the beams scattered from the different parallel planes are 
> systematically out of phase with each other unless Bragg's law is met 
> for that set of planes, so interference is destructive and adds up to nothing.
> At least that's how I understand it,
> eab
> 
> 
> 
> 
> On 07/08/2014 03:53 PM, Kianoush Sadre-Bazzaz wrote:
> >Hi
> >
> >If a sample of powder crystal (say Nickel) is shot with monochromatic
x-rays, one will observe reflections from planes that satisfy Bragg's Law.
For Ni the first four planes are (111, 200, 202, 311) with 2theta (44, 52, 76, 
93 degrees) respectively. 
> >
> >  Why doesn't one observe a reflection at, say, 45 degrees? There 
> > will be
a grain oriented in the powder such that x-rays reflect at 45 degrees and so
forth. I would expect a continuum of reflections...   
> >
> >thanks for the insight.
> >
> >Kianoush
> >

-- 

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