On 04/07/2016 2:03 PM, William Donzelli wrote:
Per his description, the 7805's input will be open. It will not try to
source any current, as it will have none to give.
I suppose there might be a little leakage.
--
Will
If his intention is to bypass the 7805 then it should have both input
and output legs cut and lifted.
John :-#)#
On Thu, Apr 7, 2016 at 4:58 PM, drlegendre . <drlegen...@gmail.com> wrote:
Err.. unless the voltage of the switcher is identical to that of the 7805,
then one device will source current, and the other will sink it.
Like putting two 6V batteries in parallel, where one is fresh and the other
weak. Current will flow until the potentials are equalized. But with two
regulated circuits, I don't see how equality can be achieved.
Not saying it's going to smoke-out, but it does seem like a wonky thing to
do.
On Thu, Apr 7, 2016 at 3:41 PM, wulfman <wulf...@wulfman.com> wrote:
You should be just fine.
On 4/7/2016 1:38 PM, Bill Sudbrink wrote:
If you have a circuit which is normally designed to
operate with an unregulated supply, through a regulator...
say unregulated +8 through a 7805 to a regulated +5 and
you want to test it independent of the +8 supply, if
you leave the unregulated rail unattached and put +5
switcher straight onto the regulated +5 rail, will you
damage the 7805? Clearly the VIN is open, but the ground
pin will still be attached. Would this push voltage
back through and screw things up?
Thanks,
Bill S.
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