On Wed, Jun 15, 2016 at 3:16 PM, Noel Chiappa <j...@mercury.lcs.mit.edu> wrote:
> > From: William Degnan > > >> For 777560/60 (standard for the console), you want A7/A3 and V4/V5 > >> 'in'. > > > I intend to use a serial terminal to access the console via M912 > > CONSOLE ROM. > > Got it; that would mean you're wanting the standard console. > > > I believe you're saying to connect A7/A3 and V4/V5 > > Right, insert jumpers A7 and A3, and also V5 and V4. > Thanks, done. Just about to try it out. > > > > I still don't understand the pattern. > > They specify the device address and vector in binary. > > A7 is the 7th bit of the address, i.e. the 0200 bit. And since the DL11 is > 'address jumper in for 0', that bit in the device's address is going to be > _0_ when the jumper is in. That would turn 777770 (remember, the device is > a > block of 8 bytes, from xxxxx0 to xxxxx7, so you can't set the low 3 bits in > the base address, they must be 0) into 777570. Similarly, A3 is 010, and > turns 777770 to 777760. Put them together, you get 777560. > > V5 = 040, V4 = 020, so they become a vector of 060. > > > What would A4, A5, A6 and V7, V6, V3 represent > > A4 = 020, A5 = 040, A6 = 0100. V7 = 0200, V6 = 100, V3 = 010. > > > OK, this makes sense, thanks. > > Is there a table with the jumpers and values somewhere? > > No, but I'll whip one up and stick it on the Computer History wiki. > > Many would appreciate this I bet. > > Specifically something that lists all jumper combos and their > > corresponding addresses? > > Well, _all_ the combinations would be 2^8 combinations (there are 8 address > jumpers), which is pretty sizeable, and I don't feel like listing them all, > but I can list a couple of the most common ones (e.g. console, second line, > etc). > > Maybe just keep it to the useful combos :-) Thanks again. b