On Mon, 2007-01-29 at 10:01 +0000, Robert Stones wrote:

> 'The side effect of this approach is that a molecule like 2,3-dimethyl 
> benzene will not be split into any fragments. On the other hand if the 
> molecule is split on terminal bonds, we would only include the large 
> fragment (and not the single atom at the end of the terminal bond). A 
> side effect of this approach is that a group like NO2 would get split up 
> into a N=O and O which may not be appropriate.'
> 
> Would it be possible to cleave TERMINAL bonds the code was changed. 
> Tried to change the code without success. 

I've modified the code to also cleave terminal bonds, but exclude 1-bond
fragments that result from this approach (i.e. all fragments will have 3
or more atoms).

>  Also cyclohexane is not 
> cleaved even though it does not have terminal bonds.

No, the code will not cleave cyclohexane since all the bonds are ring
bonds.

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Rajarshi Guha <[EMAIL PROTECTED]>
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