[EMAIL PROTECTED] wrote: > actually, set y: 1,2,3,4,5 would have 32 different combinations > > null, 1, 1 2, 1 3, 1 4, 1 5, 2, 2 2, 2 3, 2 4, 2 5, 3, 3 3, 3 4, 3 5, > 4, 4 4, 4 5, 5, 5 5, 1 2 2, 1 2 3, 1 2 4, 1 2 5, etc...., 1 2 3 4 5 > > The formula would be 2^(number of items in set)
Well that is why I said combinations of size X. I.E. Only combinations of size 3 or 4, etc. It looks like G Money groked what I was looking for. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~| Adobe® ColdFusion® 8 software 8 is the most important and dramatic release to date Get the Free Trial http://ad.doubleclick.net/clk;192386516;25150098;k Archive: http://www.houseoffusion.com/groups/CF-Community/message.cfm/messageid:258589 Subscription: http://www.houseoffusion.com/groups/CF-Community/subscribe.cfm Unsubscribe: http://www.houseoffusion.com/cf_lists/unsubscribe.cfm?user=89.70.5
