Use the GetFileFromPath() function.
Try:
<cfoutput>#GetFileFromPath("C:\Winnt\System32\driver\lmhosts.sam")#</cfoutpu
t>
It will result in lmhosts.sam being displayed.
-----Original Message-----
From: cf kaizen [mailto:[EMAIL PROTECTED]]
Sent: Friday, May 19, 2000 11:41 AM
To: [EMAIL PROTECTED]
Subject: Strip directory path to get just file name
Hi All,
If my value in a string is
c:\webshare\wwwroot\site\filename.cfm
, how I just strip it down so I can dump filename.cfm
into a variable?
I am thinking that I should access the above string
from the right side, looping through each character
until I get to the first "\". However, I don't know
where to start with the code (and, I left both cfwacks
books at home :(
Any help is very much appreciated!
Thanks!
Andy
__________________________________________________
Do You Yahoo!?
Send instant messages & get email alerts with Yahoo! Messenger.
http://im.yahoo.com/
----------------------------------------------------------------------------
--
Archives: http://www.eGroups.com/list/cf-talk
To Unsubscribe visit
http://www.houseoffusion.com/index.cfm?sidebar=lists&body=lists/cf_talk or
send a message to [EMAIL PROTECTED] with 'unsubscribe' in
the body.
------------------------------------------------------------------------------
Archives: http://www.eGroups.com/list/cf-talk
To Unsubscribe visit
http://www.houseoffusion.com/index.cfm?sidebar=lists&body=lists/cf_talk or send a
message to [EMAIL PROTECTED] with 'unsubscribe' in the body.