No, it returns pos and length of the subgroups, but you can use that
with greedy matches to find the position:
position = 0;
stTmp = REFind("^.*(a)",string,1,true);
if(stTmp.pos[1]) position = stTmp.pos[2];
This gives the last position of "a". OR you can do what you suggested
yourself in your previous post. Reverse the string and look for the
first occurrence.
> -----Original Message-----
> From: Adam Haskell [mailto:[EMAIL PROTECTED]
> Sent: 12 January 2005 13:16
> To: CF-Talk
> Subject: Re: Regular Expression (searching from the end)
>
> Alernatively you can use refind and return the array thing I beleive
> it returns the POS and Len of all the times it found then you could
> just look at the last element in the array, TIMTOWTDI.
>
>
> Adam H
>
>
> On Wed, 12 Jan 2005 11:39:24 +0000, Andrew Dixon
<[EMAIL PROTECTED]>
> wrote:
> > Hi Everyone.
> >
> > I need to find the last occurance of a character in a string. Is
there
> > a way I can use a regular expression to search the string from the
end
> > backwards for the character? Or is there another way I can do it
using
> > a CF function. At the moment I have a conditional loop that uses the
> > Find() function to search until it returns 0 and then report the
> > previous value as the last occurance. This works fine, but I feel
> > there should be a better way.
> >
> > Thanks
> >
> > Andrew.
> >
> >
>
>
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