ORDER BY Date will include the year, so 01/JAN/1940 will always appear
before 02/DEC/1999 even though on 01/DEC/2000 it is only one day to the
second date but 31 days to the first. That is why I need the datecompare
function (although it is slightly more complicated than just
datecompare(date, now()) it is actually
#abs(datediff("D", createdate(year(now()), month(date), day(date)), now()))#
but that isn't the point.
----- Original Message -----
From: "DeVoil, Nick" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc: "'James Smith'" <[EMAIL PROTECTED]>
Sent: Tuesday, September 05, 2000 2:23 PM
Subject: RE: SQL ORDER BY Problem
> Let's hope this one gets there a bit quicker..
>
> James
> What's wrong with SELECT Date FROM Dates ORDER BY Date?
> (You're not really using the name Date I guess)
> Nick
>
>
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