in MySQL you can do this:

SELECT e.eventID, e.eventName,
  (SELECT GROUP_CONCAT(ed.eventDate, ', ') FROM EventDates ed
   WHERE ed.EventID = e.EventID AND ed.eventDate > Now()) as eventDatesList
FROM Events e

This will give you nicely formatted list of all the dates for each event

(i havent checked the exact syntax. if it doesn't work, I'll look it up)

----- Original Message ----- 
From: "Adrian Lynch" <[EMAIL PROTECTED]>
To: "CF-Talk" <cf-talk@houseoffusion.com>
Sent: Wednesday, November 16, 2005 5:02 PM
Subject: RE: Query Question


>I don't know about efficient, but try
>
> SELECT TOP 1 eventID....
>
> That's if it's SQL Server, the over DBs will have something similar
>
> Ade
>
> -----Original Message-----
> From: Russ [mailto:[EMAIL PROTECTED]
> Sent: 16 November 2005 21:56
> To: CF-Talk
> Subject: Query Question
>
>
> I have 2 tables, for the sake of simplification lets say they look like
> this:
>
>
>
> EVENT
>
> eventID
>
> eventName
>
>
>
>
>
> EVENTDATES
>
> eventID
>
> eventDate
>
>
>
> Each event would be in the event table once, and possibly multiple times 
> in
> the eventDates table.  I want to have a query return one record for each
> event with the next eventDate from the eventDates table.
>
>
>
> So basically something like:
>
>
>
> Select eventID, eventName, eventDate from event inner join eventDates on
> event.eventID=eventDates.eventID where eventDate>#Now()#
>
>
>
> But I only want 1 record returned for each event. I know I can probably
> order by eventID and then do a cfoutput groupby, but I don't really want 
> all
> those records coming back (I mean it will basically be number of records 
> in
> the event table * number of records in the eventDates table).
>
>
>
> Is there a more efficient way of doing this?
>
>
> 

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