Yes but you have to factor in the frequency of visitors by time as well, the
chance increases at a certain time and decreases at another time, unless you
are absolutely certain the time distrobution of visitors to your site is
exact and a user comes ever 5 minutes on the nose...
Jeremy
-----Original Message-----
From: Chapman, Katrina [mailto:[EMAIL PROTECTED]]
Sent: Thursday, October 12, 2000 2:44 PM
To: CF-Talk
Subject: RE: slightly ot: math question, needed for cold fusion
programming
That would be 1/2592:1 or 3.85802e-4:1 or .000385802:1
That's the chance that two people will hit at the same exact millisecond.
--K
-----Original Message-----
From: Warrick, Mark [mailto:[EMAIL PROTECTED]]
Sent: Thursday, October 12, 2000 11:33 AM
To: CF-Talk
Subject: RE: slightly ot: math question, needed for cold fusion
programming
Interesting math problem. Perhaps there's a statistical math mailing list
that could help you out somewhere?
I'd check your local college's web site.
Here's my guess:
1,000 ms = 1 second
1,000 sec * 60 = 60 seconds = 60,000 ms
60,000 ms * 60 = 1 hour = 3,600,000 ms
3,600,000 * 24 = 1 day = 86,400,000 ms
86,400,000 * 30 = 1 month (approx) = 2,592,000,000
1,000,000 hits / 2,592,000,000 ms = a number my calculator won't even reach.
How's that for a chance? Let's put it this way - it's most likely not going
to happen.
---mark
--------------------------------------------------------------
Mark Warrick
Phone: (714) 547-5386
Efax.com Fax: (801) 730-7289
Personal Email: [EMAIL PROTECTED]
Personal URL: http://www.warrick.net
Business Email: [EMAIL PROTECTED]
Business URL: http://www.fusioneers.com
ICQ: 346566
--------------------------------------------------------------
> -----Original Message-----
> From: Gavin Myers [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, October 11, 2000 10:02 AM
> To: CF-Talk
> Subject: slightly ot: math question, needed for cold fusion programming
>
>
> Lets say you have 1 page that scores 1,000,000 unique visitors a month
>
> here's what I came up with:
>
> 1,000,000/30/24/60/60/1000 = 0.000385
>
> So that means that 0.0003 people a milisecond hit the sight, correct?
> what is the % chance of 2 people hitting on the same milisecond (and math
> equation for that?)
> ------------------------------------------------------------------
> ------------
> Archives: http://www.mail-archive.com/cf-talk@houseoffusion.com/
> To Unsubscribe visit
> http://www.houseoffusion.com/index.cfm?sidebar=lists&body=lists/cf
> _talk or send a message to [EMAIL PROTECTED] with
> 'unsubscribe' in the body.
----------------------------------------------------------------------------
--
Archives: http://www.mail-archive.com/cf-talk@houseoffusion.com/
To Unsubscribe visit
http://www.houseoffusion.com/index.cfm?sidebar=lists&body=lists/cf_talk or
send a message to [EMAIL PROTECTED] with 'unsubscribe' in
the body.
----------------------------------------------------------------------------
--
Archives: http://www.mail-archive.com/cf-talk@houseoffusion.com/
To Unsubscribe visit
http://www.houseoffusion.com/index.cfm?sidebar=lists&body=lists/cf_talk or
send a message to [EMAIL PROTECTED] with 'unsubscribe' in
the body.
------------------------------------------------------------------------------
Archives: http://www.mail-archive.com/cf-talk@houseoffusion.com/
To Unsubscribe visit
http://www.houseoffusion.com/index.cfm?sidebar=lists&body=lists/cf_talk or send a
message to [EMAIL PROTECTED] with 'unsubscribe' in the body.
