You could use a CASE statement, but it might just be easier to get the
values separately and do the check and division in CF

On Jan 17, 2008 10:25 AM, morchella <[EMAIL PROTECTED]> wrote:

> actually the + 0.0000001 was just my old was of avoiding / by zero error
> thats why i want to test to see if result is zero & then not / into it.
>
> On Jan 17, 2008 10:14 AM, Mark Kruger <[EMAIL PROTECTED]> wrote:
> > The COUNT( ) function will never return NULL.  So "isNull(count(*))"
> will
> > never trigger.  Count(*) will always return an int - so using isNULL and
> > "count" together is not possible - plus you are mixing data types if you
> are
> > trying to return a 0.00001 to a function call designed to return an int.
> >
> >
> > -----Original Message-----
> > From: morchella [mailto:[EMAIL PROTECTED]
> > Sent: Thursday, January 17, 2008 9:03 AM
> > To: CF-Talk
> > Subject: SQL: ISNULL, NULLIF problem
> >
> > i have been trying to figure out how to check for null like whats done
> in
> > this url:
> >
> http://www.bennadel.com/blog/984-Using-NULLIF-To-Prevent-Divide-By-Zero-Erro
> > rs-In-SQL.htm
> >
> >
> > SELECT
> > (
> > ISNULL(
> > (45 / NULLIF( 0, 0 )),
> > 0
> > )
> > ) AS value
> >
> > how would i re write the code below to check for null i can then get rid
> of
> > the + 0.00000001
> >
> > (SELECT COUNT(*)
> > FROM Emp
> > WHERE emp_assID = rEmp.empID AND addSale = 1) * 100 / (SELECT COUNT(*) +
> > 0.00000001 FROM Emp WHERE emp_assID = rEmp.empID AND ((Emp.Qal = 4) OR
> > (Emp.addSale = 1))) AS perEmp
> >
> >
> > i tried:
> > (SELECT ISNULL( COUNT(*)
> > FROM Emp
> > WHERE emp_assID = rEmp.empID AND addSale = 1) / NULLIF( (SELECT COUNT(*)
> > FROM Emp WHERE emp_assID = rEmp.empID AND ((Emp.Qal = 4) OR (Emp.addSale=
> > 1))), 0 )), 0
> > )
> > ) AS perEmp
> >
> > but i get Incorrect syntax near the keyword 'FROM'.
> > any help would be great...
> > thanks
> >
> >
> >
> >
>
> 

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