select avg(connects + acd) from (
SELECT da.connects as connects, sum(ad.acd) as acd
FROM dialeragent da, agentDaily ad WHERE da.employeeID = ? AND da.employeeID
= ad.employeeID AND da.dateWorked = ? AND ad.dateWorked = ? group by
connects
)

On Thu, Mar 10, 2011 at 2:20 PM, Greg Morphis <gmorp...@gmail.com> wrote:

> So you want : (13 + 192) / 2?
> Or do you need 192/13 ?
>
>
> On Thu, Mar 10, 2011 at 2:07 PM, Torrent Girl <moniqueb...@gmail.com>wrote:
>
>>
>> >can you provide a couple rows of data with no functions? just the ad.acd
>> and
>> >the da.connects?
>> >and what you would like for it to show? whenever you use an aggregate
>> >function like avg you have to use group by
>> >like
>> >
>> >select studentId, avg(grade)
>> >from grades
>> >group by studentId
>> >
>> >
>> >
>> >On Thu, Mar 10, 2011 at 1:52 PM, Torrent Girl <moniqueb...@gmail.com>
>> wrote:
>> >
>> >>
>> Do you mean let you see the returned data?
>>
>> Here is my query (there is a group by) :)
>>
>> SELECT da.connects, sum(ad.acd) as acd FROM dialeragent da, agentDaily ad
>> WHERE da.employeeID = ? AND da.employeeID = ad.employeeID AND da.dateWorked
>> = ? AND ad.dateWorked = ? group by connects
>>
>> here is what it returns.
>>
>> ACD     CONNECTS
>> 13      192
>>
>> I need to total the AVG of these two numbers.
>>
>> 

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