Nope, that doesn't work.

----- Original Message -----
From: laszlo <[EMAIL PROTECTED]>
Date: Wednesday, March 13, 2002 4:06 pm
Subject: Re: SQL help please

> select ... count(paycatid) as samepaycatid.... group by paycatid
> 
> laszlo
> 
> 
> [EMAIL PROTECTED] wrote:
> 
> > Anyone?
> >
> > Bueller?  Bueller?
> >
> > ----- Original Message -----
> > From: [EMAIL PROTECTED]
> > Date: Wednesday, March 13, 2002 2:51 pm
> > Subject: SQL help please
> >
> > > Brain not working.... Must help...
> > >
> > > Here's my data set:
> > >
> > > employeeid startdate enddate paycatid
> > > ----------- ----------- ----------- -----------
> > > 936 2002-02-08 2002-02-08 1
> > > 936 2002-02-11 2002-02-11 1
> > > 936 2002-02-12 2002-02-12 1
> > > 936 2002-02-13 2002-02-13 11
> > > 936 2002-02-14 2002-02-14 1
> > > 936 2002-02-15 2002-02-15 1
> > > 936 2002-02-18 2002-02-18 11
> > > 936 2002-02-19 2002-02-19 11
> > > 936 2002-02-20 2002-02-20 11
> > > 936 2002-02-21 2002-02-21 11
> > > 936 2002-02-22 2002-02-22 11
> > > 936 2002-02-25 2002-02-25 7
> > > 936 2002-02-27 2002-02-27 7
> > >
> > > What I'm wondering is how do I get something like:
> > >
> > > employeeid startdate enddate same paycatid in a row paycatid
> > > ----------- ----------- ----------- ----------- ----------
> > > 936 2002-02-08 2002-02-12 3 1
> > > 936 2002-02-13 2002-02-13 1 11
> > > 936 2002-02-14 2002-02-15 2 1
> > > 936 2002-02-18 2002-02-22 5 11
> > > 936 2002-02-25 2002-02-27 2 7
> > >
> > > I'm using SQL Server 7.
> > >
> > >
> > >
> > 
> 
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