================
Comment at: test/cpp11-migrate/UseAuto/iterator.cpp:67-70
@@ +66,6 @@
+
+ // declarator-id is not the same type as initializer expression. No transform
+ // should happen.
+ std::vector<int>::iterator I2 = myI;
+ // CHECK: std::vector<int>::iterator I2 = myI;
+
----------------
Dmitri Gribenko wrote:
> Edwin Vane wrote:
> > Dmitri Gribenko wrote:
> > > So this transformation was not being done even without this change?
> > That's right. The point of that code originally was to get at the
> > as-written source of the conversion operator. In this case, the source type
> > of the conversion op was not the same as the dest so the change wasn't
> > made. Now we abort on any conversion ops, even those whose source type is
> > the same as the dest (if that's even possible) because of the side effect
> > thing you mentioned.
> I think we can drop [the loop] then. This will not break the test, and
> conversion operator that converts to itself will not be called implicitly.
Just to be clear, you're suggesting something like:
const Expr *E = Construct->arg_begin()->IgnoreParenImpCasts();
const Expr *E2 = E->IgnoreConversionOperator();
if (E2 != E) {
return;
}
That is, shall we abort on a conversion expression or do we just update E with
the result of `IgnoreConversionOperator()`? Or are these two options really
equivalent since conversion expressions where the source and dest type are the
same never happen?
http://llvm-reviews.chandlerc.com/D392
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