Chris, > > I'm currently trying to remove some of the warnings spit > out on me by > > the > > VC++ compiler (mostly warnings about possible loss of precision) and > > recognized, that the bitwith (size of a type in bits) is > represented > > using different types all over the place: sometimes unsigned, > > sometimes uint32_t and sometimes it's even uint64_t. I really would > > like to change that to a more consistent scheme, but need > some advice > > which type to choose. > > Since I > > think we can't expect to get anything terribly large as the > bitwidth > > of a type I'ld say let's go for uint32_t. > > Hi Hartmut, > > We should go with uint64_t in general. There can be large > arrays (for example) on 64-bit targets that need this. For > "known little things" like integer types, uint32_t would be > sufficient, but it is probably better to be consistent and > use uint64_t for everything.
IIUC, the bitwidth is most of the time the number of bits needed to represent the size, i.e. 32 for uint32_t. In this case 64 is the largest number these kind of variables will ever hold, no? Regards Hartmut _______________________________________________ cfe-dev mailing list [email protected] http://lists.cs.uiuc.edu/mailman/listinfo/cfe-dev
