Roger, that's perfect. Thank you

On Wed, Oct 16, 2013 at 6:41 PM, Roger Hui <[email protected]>wrote:

>    x=: 1 2.5 3.5 10 12 30
>
>    c=: _1 0 1{~((#x)#3)#:i.3^#x
>    ] d=: (15 = c+/ .*x)#c
> _1 _1 _1  1  1 0
> _1  1  1  1  0 0
>  1 _1 _1 _1  0 1
>  1  1  1 _1 _1 1
>
>    d +/ .*x
> 15 15 15 15
>
> See also http://www.jsoftware.com/jwiki/Essays/Odometer<
> http://www.jsoftware.com/jwiki/Essays/Odometer?highlight=%28xkcd%29>
>
>
> On Wed, Oct 16, 2013 at 3:33 PM, Joe Bogner <[email protected]> wrote:
>
> > I'm working on a question that I was hoping J could help answer.
> >
> > I have a overall sum on a report and I'm trying to figure out what line
> > items went into it. The line items can be ignored, added or subtracted.
> >
> > In other words, given a value let's say 15, what combinations of add,
> > subtracting or ignoring numbers of a list would result in that sum?
> >
> > I found a solution on the right rack in J
> >
> >
> >
> http://stackoverflow.com/questions/4632322/finding-all-possible-combinations-of-numbers-to-reach-a-given-sum
> >
> > (]#~15=+/@>)(]<@#~[:#:@i.2^#)1 5 10 2.5 2.5
> >
> >
> > That only appears to work on the add case. For example, if it worked as I
> > desired, it would output
> >
> >
> > (]#~15=+/@>)(]<@#~[:#:@i.2^#) 10 2.5 12 3.5 1 30
> >
> > 10 3.5 2.5 -1
> >
> > Any ideas on how to approach this or any solutions handy?
> >
> > This post sounds like the right approach but I don't know how to
> implement
> > it:
> >
> >
> >
> http://stackoverflow.com/questions/10943562/find-all-the-addition-and-subtraction-combinations-from-an-array-of-numbers
> >
> > My report has between 10-55 possible combinations of numbers on it
> > depending on what the report is run on. The specific one I'm solving
> right
> > now has 29
> >
> > Thanks
> > ----------------------------------------------------------------------
> > For information about J forums see http://www.jsoftware.com/forums.htm
> >
> ----------------------------------------------------------------------
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