Personally, I thought it was great that the original 1r998 will give 513 for the tenth sequence of three digits -- but that is because each number occupies three digits and the value which comes after 512 is 1024, and these values are combined by adding (so the leading 1 from 1024 adds to the trailing 2 from 512).
But I figured that going there in the first email would be too much of a distraction. Thanks, -- Raul On Tue, Aug 23, 2016 at 1:14 PM, Skip Cave <[email protected]> wrote: > You can add one more power of two on the list: > > 10{._3]\2}.34j32":1000000000000000000000000r9980 > 00000000000000000000001 > > 001 > > 002 > > 004 > > 008 > > 016 > > 032 > > 064 > > 128 > > 256 > > 512 > > Skip Cave > Cave Consulting LLC > > On Tue, Aug 23, 2016 at 10:08 AM, Raul Miller <[email protected]> > wrote: > > > 9{._3]\2}.34j32":1r998 > > 001 > > 002 > > 004 > > 008 > > 016 > > 032 > > 064 > > 128 > > 256 > > > > (A variation on something Christopher Carmack pointed out...) > > > > -- > > Raul > > ---------------------------------------------------------------------- > > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
