Miodrag wrote: > Very nice problem, went against my initial guess anyway. I, however, > get the probability that the denominator is not divisible by prime p > to be p/(1+p), i.e. probability that it is divisible by prime p is > 1/(1+p).
You're right: not quite as spectacular as my claim, but still not what I would have guessed. Best wishes, John ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
