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In a message dated 01/31/2002 7:55:49 AM Eastern Standard Time,
[EMAIL PROTECTED] writes:
> I think it's bore x bore x stroke x #cyl x .7854 (instead of .7894)? That's
> what I've always used. A 396 +.060 is 408.3 cubes - I have the same
engine.
> BTW, if you take cid times 0.01639, you get your engine size in liters.
>
> Dale
Correct. It is just the volume of all the cylinders.
Total cu in => number of cylinders * volume of one cylinder
we know:
volume of a cylinder = area of the base circle of cylinder * height of the
cylinder
area of circle = PI * R * R (where R is the radius of circle in inches)
R = bore / 2 (inches)
stroke = height of the cylinder (inches)
so:
Total cu in = ( PI * R * R ) * cyl height * # cyl
= ( PI * (bore/2) * (bore/2)) * stroke * # cyl
= ( PI / 4 * bore * bore) * stroke * # cyl
= .7854 * bore * bore * stroke * # cyl
So the .7854 is just PI / 4.
Ain't math great? B-)
---------------------
Kurt Ehrhardt
ACES #1280
66 Malibu
66 SuperSport
Enfield, CT
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