At 11:01 AM 9/4/2000 -0100, you wrote: I broke out the CCNA book, to practice readings for a couple of up & coming interviews (this week). comments in line 192.16.12.0 is my given class C I need 10 users (hosts- 11 counting the Ethernet Interface) So this means I must take 2 to the 4th (16-2= 14 usable) on the mask side & that leaves me with 2 to the 4th on the Host addressing side (same 14 usable). So far, so good. How to I proceed with the first to last IP's available... i.e. My nature tendency, it to look @ things this way... 192.16.12._ to _, does this mean I am now in the 16's if I recall. 192.16.12.1 thru 15, 192.16.12.16 thru 31, 192.16.12.32 thru 63, etc... You now have a subnet mask of 255.255.255.240 To find the first host addie, subtract from 256. ( or take the number of 0's in the new mask and do 2^x, in this case 2^4=16. 256-240 = 16. First network ID is 192.16.12.16 It'll now be in increments of sixteen, so next subnet is 192.16.12.32, 192.16.12.48, etc. First host ID is 192.16.12.17 and broadcast is 192.16.12.31---second subnet, the .32 one first host is 33 and broadcast is 47. Most people on the list would find the following too simplified, but when I was first trying to figure out subnetting for the MCSE TCP/IP exam, I put my simplified explanation on the web--it's simply how to do it, more or less ignoring the why. It's at http://www.bansen.com/neko/subnet.html HTH Scott ___________________________________ UPDATED Posting Guidelines: http://www.groupstudy.com/list/guide.html FAQ, list archives, and subscription info: http://www.groupstudy.com Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
