It would be the first 2 bits in the 3rd octet. Go back to subnetting these
are network numbers with the netmask of 255.255.192.0 First 2 bits make
192. 256-192 = 64.
64, 128, 192
Scott P.
"John lay" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Guys,
>
> While studying for the CCDA, I found the following question in one of the
> exam preparation sites.
>
> The following IP addresses can be summaried by which bit of the 3rd octet
> 172.16.0.0, 172.16.64.0, 172.16.128.0, 172.16.192.0 ---> 1st bit, first 2
> bit, first 4 bit, last 6 bit
>
> I don't think that the following addresses could be summarized on any bit
of
> the 3rd octet.
> If you have a look to the 3rd octet
> 172.16.0.0 ---> 172.16.00000000.0
> 172.16.64.0 ---> 172.16.01000000.0
> 172.16.128.0---> 172.16.10000000.0
> 172.16.192.0---> 172.16.11000000.0
>
> Could someone verify this with me guys ?
> Thanks a lot
>
>
>
>
>
>
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