Somebody tell me if I have this wrongt.
The STP algorithm is executed whenever a unexpected BPDU is recieved, or a
number of expected BPDU's are NOT recieved. A BPDU is Layer-2 Multicast out
of all ports on a switch at regular intervals.
A port is placed in the blocking state if it recieves one of it's own
BPDU's.
In the blocking state, all frames except for BPDU's are ignored. BPDU's are
still transmitted and recieved on a Blocking port.
----Original Message Follows----
From: "AUX0" <[EMAIL PROTECTED]>
Reply-To: "AUX0" <[EMAIL PROTECTED]>
To: "Leigh Anne Chisholm" <[EMAIL PROTECTED]>, "Jared Carter"
<[EMAIL PROTECTED]>, "'Jon Mitchell'" <[EMAIL PROTECTED]>,
<[EMAIL PROTECTED]>
Subject: Re: STP question
Date: Mon, 2 Oct 2000 08:35:52 -0400
No, putting a pc on a switch port WILL cause the STP algorithm to execute.
----- Original Message -----
From: "Leigh Anne Chisholm" <[EMAIL PROTECTED]>
To: "Jared Carter" <[EMAIL PROTECTED]>; "'Jon Mitchell'"
<[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Friday, September 29, 2000 7:35 PM
Subject: RE: STP question
> Actually, Spanning Tree only runs if it detects the presence new or
absence of expected BPDU's. Plugging a PC into a switch port will not cause
the Spanning Tree Algorithm to execute.
>
>
> -- Leigh Anne
>
> > -----Original Message-----
> > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
> > Jared Carter
> > Sent: Friday, September 29, 2000 4:37 PM
> > To: 'Jon Mitchell'; '[EMAIL PROTECTED]'
> > Subject: RE: STP question
> >
> >
> > Spanning Tree will run its algorithm every time a port is plugged
> > in (unless
> > Portfast is enabled...) and ensure a loop free topolgy. The first port
up
> > will not necessarily be the one that stays in forwarding, it depends on
> > several variables... bridge ID, cost to root, port priority...
> > all of which
> > are sent out in STP BPDUs.
> >
> > I would recommend you get a copy of the Cisco Press book Cisco LAN
> > Switching. The two chapters on STP (and the rest of the book, too) are
> > probably the best written. Well worth the $60 or so.
> >
> > /Jared
> >
>
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