Right, I got the same thing, *but* - the two addresses are the same major
Class C network, 192.168.13.0. So, couldn't you conceivably have two
stations with the same IP address? For example, 192.168.13.81/29, and
192.168.13.81/30?
----- Original Message -----
From: Chris Larson
To: [EMAIL PROTECTED] ; [EMAIL PROTECTED]
Sent: Friday, October 06, 2000 8:25 PM
Subject: Re: Doyle Ch. 7 Troubleshooting Question #1
If you look at the bits the 29 bit mask combined with the addressing in the
4th octet make the network
255.255.255.01010
The 28 bit mask with 90 address make the network 0101
These are hosts within their respective subnets.
----- Original Message -----
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, October 05, 2000 9:17 AM
Subject: Doyle Ch. 7 Troubleshooting Question #1
> RTA and RTB's respective ethernet segments have me bamboozled. The look
like they're the same subnet address!
>
> RTA: 192.168.13.86/29
> RTB: 192.168.13.90/28
>
> In spite of the mask being different, the network portions of both
addreses consist of the 64 and 16 bits being turned on. Is this not
illegal?
>
> Thanks in advance -
>
> Bradley J. Wilson
> CCNA, CCDA, MCSE, NNCSS, CNX-A, MCT, CTT
>
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