This is a matter of how the question was phrased.
If a class B address had 11 bits of subnetting, then the mask is
255.255.255.224. Why?
Because a class B address has NO bits of subnetting to begin with. You
take the binary,
11111111.11111111.00000000.00000000, and to that you add 11 bits, and
you'll get:
11111111.11111111.11111111.11100000 or 255.255.255.224.
Does this help?
Craig
At 08:47 AM 10/14/2000 +0000, you wrote:
>Default netmask for class B is 255.255.0.0 with 11 subnet mask you will
>have /27
>ie 255.255.255.224
>
>it's bit confusing though..
>
>Nobody
>Keith Woodworth <[EMAIL PROTECTED]> wrote in article
><[EMAIL PROTECTED]>...
> >
> > Ive been at this for quite a while and the odd subnet question still gets
> > me.
> >
> > Boson question:
> >
> > IP address 172.16.3.57 w/ and 11-bit subnet mask. What are valid hosts?
> >
> > I think ok class B, but I look at 11 bits as 255.224.0.0
> > (11111111.11100000.0.0) which does not go with the choices of answers I
> > had.
> >
> > I got it wrong as the answer says an 11-bit mask is 255.255.255.224 when
> > using a class b address. Is the mask there not 27 bits? What am I missing
> > there? How do they get the above mask w/11 bits?
> >
> > The valid hosts were:
> >
> > 172.16.3.33-172.16.3.62, which I think is valid for a 27 bit mask
> >
>
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