Hi Sudarshan,
This is my calculation:
172.16.00001010.00010000 (10.16)
172.16.00001011.00000100 (11.4)
172.16.00001011.00001000 (11.8)
|===========| = longest match...
8 + 8 + 7 bits to mask the network part (the common elements) = 23
Address = 172.16.10.0/23
Tom
"Sudarshan Narasimhachari" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hi Tom,
>
> How did you get /23 ? Is it a typo ? I think the summarized route would
> be 172.16.10.0/24
>
> BRgds
> Sudarshan
> --- Tom Keough <[EMAIL PROTECTED]> wrote:
> > Hi Jin,
> > I just read about route summarization a couple days ago and from my
> > little
> > knowlege I would say the answer is:
> > 172.16.10.0/23
> > I wrote out the addresses in binary and looked for the "longest
> > match" and
> > thus the answer above...
> > Tom
> > "Zhang Jin" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > Hi group,
> > > I am preparing routing 2.0 exam.And I got a question about
> > > summarization,that is:
> > > please see following figure:
> > >
> > > |
> > > |
> > > | other network
> > > |
> > > RouterA-----------------RouterB
> > > | | 172.16.10.16/29
> > > | |
> > > | 172.16.11.4/30
> > > | |
> > > | | 172.16.11.8/27
> > > RouterC
> > >
> > > Question is:when I use manual summarization configuration,what is
> > the
> > > summary network address look like:
> > >
> > > some one ever said : 172.16.1.0/24
> > > Is it correct?why?
> > >
> > > I need your help.Thanks
> > >
> > > Dean
> > >
> > > _________________________________
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