In route aggregation you normally match the number of
bits from left to right until a mismatch occurs and
that's how you get 172.16.0.0 /22 since for the third
octet
00000001
00000010
00000011
the common bits are the first 6 bits
hope this helps
suaveguru
--- Hunt <[EMAIL PROTECTED]> wrote:
> Can anyone please explain to me how to aggregate the
> following 3 routes?
>
> 172.16.1.0 /24
> 172.16.2.0 /24
> 172.16.3.0 /24
>
> into...
>
> 172.16.0.0 /22
>
>
>
>
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