this is taken from there white paper
The following process describes the move from shared tree to source tree in
more detail:
1 Receiver joins a group; leaf Router C sends a Join message toward RP.
2 RP puts link to Router C in its outgoing interface list.
3 Source sends data; Router A encapsulates data in Register and sends it to
RP.
4 RP forwards data down the shared tree to Router C and sends a Join message
toward Source. At
this point, data may arrive twice at Router C, once encapsulated and once
natively.
WHY WHY WHY ...it dosent` say why it will arrive nativley.....GIT
5 When data arrives natively (unencapsulated) at RP, RP sends a
Register-Stop message to Router
A.(i can understand that)
6 By default, reception of the first data packet prompts Router C to send a
Join message toward
Source.
7 When Router C receives data on (S,G),(???????) it sends a Prune message
for Source up the shared tree.
WHY WHY WHY !!!!?????
8 RP deletes the link to Router C from outgoing interface of (S,G). RP
triggers a Prune message
toward Source.
WHY WHY !!!!!
AM I MISSING SOMETHING......SORRY IVE BEEN AT IT ALL DAY ...
and my brain now hurts
TIA
steve
S6234
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